Tina is saving to buy a notebook computer. she has two options. the first option is to put $400 away initially and save $20 every month. the second option is to put $300 away initially and save $40 every month. after how many months would tina save the same amount using either option? how much would she save with either option? after [ ] months, tina will save $[ ] with either option.

Her savings amounts after x months will be ...

... 400 + 20x

or

... 300 + 40x

You want to find x such that these are the same amount. So, we equate these values and solve for x.

... 400 + 20x = 300 + 40x

... 0 = -100 + 20x . . . . . . . . . subtract the left side

... 0 = -5 + x . . . . . . . . . . . . . divide by the coefficient of x

... 5 = x . . . . . . . . . . . . . . . . add the opposite of the constant

Using the first option, we find the savings amount to be

... 400 + 20·5 = 500

After 5 months, Tina will save $500 with either option.

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Once you have the expressions for the options, it is convenient to let a graphing calculator tell you the point where they are the same.

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

answer: 12

step-by-step explanation:

because yes