What is the solution to the above system of equations?

The solution to the system of equations are  x = 7 and y = -1

2x + 3y = 11 equation 1

3x + 3y = 18 equation 2

The equations given are simultaneous equations. They would be solved using the elimination method.

In order to use the elimination method, take the following steps:

1. Subtract equation 1 from equation 2

x = 7

2. Substitute for x in equation 1

2(7) + 3y = 11

3. Expand the bracket

14 + 3y = 11

4. Combine similar terms

3y = 11 - 14

5. Add similar terms

3y = -3

6. Divide both sides of the equation by 3

y = - 1

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(x , y) = (7, - 1)

2x + 3y = 11 → (1)

3x + 3y = 18 → (2)

subtracting (1) from (2) term by term eliminates the y- term

(3x - 2x) + (3y - 3y) = (18 - 11)

x + 0 = 7 ⇒ x = 7

substitute x = 7 into either of the 2 equations and solve for y

(1) → (2 × 7) + 3y = 11

14 + 3y = 11

subtract 14 from both sides

3y = 11 - 14 = - 3

divide both sides by 3

= - 1

solution is (7 , -1)

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1