Can u me set up the sum of three consecutive integers is 1623. any is appreciated.

n, n + 1, n + 2 - three consecutive integers

1623 - the sum

The equation:

n + (n + 1) + (n + 2) = 1623

n + n + 1 + n + 2 = 1623

3n + 3 = 1623     |subtract 3 from both sides

3n = 1620     |divide both sides by 3

n = 540

n + 2 = 540 + 2 = 542

n + 4 = 540 + 4 = 544

540, 542, 544.

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632

answer: c

substitute in the values.

for a:

f(0) = 0 + 9

f(0) = 9

a is a solution.

for b:

f(7) = 14 + 9

f(7) = 23

b is a solution.

for c:

f (3) = 6 + 9

f(3) = 15

c is not a solution. it's supposed to be 14.

for d:

f(2) = 4 + 9

f(2)= 13

d is a solution.