Aline has slope 5/6and y–intercept −3. which answer is the equation of the line? y=56x+3 y=56x−3 y=3x+56 y=−3x+56

Option B is correct. The required equation of the line is expressed as y = 5/6 x - 3

The expression for calculating the equation of a line is expressed as:

y = mx+ b where;

m is the slope of the line

b is the y-intercept

Given the following parameters

Slope m = 5/6

y-intercept = -3

Substitute the given parameters into the formula as shown:

y = mx + b

y = 5/6x + (-3)

y = 5/6 x - 3

Hence the required equation of the line is expressed as y = 5/6 x - 3

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The equation of a line is y = mx+b where m is the slope and b is the y-intercept.

The slope is 5/6 and y-intercept is -3

The equation would be y = 5/6m - 3

a) t'(-3, 6) and v'(0, 3)  

step-by-step explanation:

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