Juan’s age is 5 years more than twice margo’s age. the sum of their ages is 29 years. find their ages

x Margo's age

Jaun + Margo

(2x+5) + x = 29

3x = 24

x = 8, Margo's age. Jaun 21 2*8+5

And to check...

sum = 29

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

0 is its x and y coordinate