Length of the rectangle 11 cm, width 3x, find the perimeter of the rectangle

Length of the rectangle 11 cm, width 3X, find the perimeter of the rectangle.

The perimeter of a rectangle is calculated by adding its four sides that are equal two to two.

Perimeter = 2*Length + 2*width = 2*11cm +2*3Xcm = 22cm + 6*Xcm

Answer : perimeter = 22cm + 6*Xcm

Hope this helps!

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

l.jnl.j/n.m,lm,

step-by-step explanation: