Kevin ran 4 miles more than steve ran. the sum of their distance is 26 miles. how far did steve run? the domain of the solution is (0, 4, 11, 22) a. define your variable b. write algebraic expressions for the distances each person ran. c. write an equation that can you solve the problem. d. solve the equation. e. check your answer. the answer is 11 i think but i need you to do a through e

In a test for esp (extrasensory perception), the experimenter looks at cards that are hidden from the subject. each card contains either a star, a circle, a wave, a cross or a square.(five shapes) as the experimenter looks at each of 20 cards in turn, the subject names the shape on the card. when the esp study described above discovers a subject whose performance appears to be better than guessing, the study continues at greater length. the experimenter looks at many cards bearing one of five shapes (star, square, circle, wave, and cross) in an order determined by random numbers. the subject cannot see the experimenter as he looks at each card in turn, in order to avoid any possible nonverbal clues. the answers of a subject who does not have esp should be independent observations, each with probability 1/5 of success. we record 1000 attempts. which of the following assumptions must be met in order to solve this problem? it's reasonable to assume normality 0.8(1000), 0.2(1000)%30 approximately normal 0.8(1000), 0.2(1000)% 10 approximately normal srs it is reasonable to assume the total number of cards is over 10,000 it is reasonable to assume the total number of cards is over 1000

1/2+1/6-3/4 simplify the given expression leaving the answer in improper fraction form.

Will make ! for correct answer the dot plot below shows the number of toys 21 shops sold in an hour.is the median or the mean a better center for this data and why? a. median; because the data is not symmetric and there are outliersb. median; because the data is symmetric and there are no outliersc. mean; because the data is symmetric and there are no outliersd. mean; because the data is skewed and there are outliers