It took john 4 hours from his home to drive to leakey, tx.. on the way home his speed was reduced by 20 mph due to heavy traffic and took 7 hours. how far is it to leakey from john's home?

Let the speed at which John is going towards Leakey = x mph

Time taken to reach Leakey = 4 hours

Distance = speed * time

So let the distance of Leakey from John's house be 4x ............. (1)

Speed while returning was 20 mph less = (x-20)

Time taken was= 7 hours

distance = (x-20)*7  ................(2)

As the distance remains the same, equation 1 = equation 2

So, the speed is mph

Distance = 4x

=

Hence, the distance of Leakey from John's house is 186.667 miles.

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