If one student rides in front seat and three in the back seat how many ways can the 4 students be arranged in car

Since there are 4 students in total ,

There are 4 choices for who is going to sit in the front. The remaining 3 students can sit at the back in 6 ways( 3choices for the extreme left student followed by 2 choices for the student sitting in the middle followed by one choice for the student sitting at the extreme right).

Therefore, the total number of ways will be 4 time 6 or 24ways

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.

step-by-step explanation:

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