Ty and gajge are both football players who averaged 4 yards per run in yesterday’s football game. the statistics from that game are shown in the table below. player name # of carries average yards gained per run longest run (yards) shortest run (yards) ty 15 4.0 6 2 gajge 10 4.0 19 2 which statement best describes the data? the lengths of ty’s runs have greater variability because ty had more rushing attempts. the lengths of gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs. ty’s and gajge’s runs have the same variability because they both average 4.0 yards per carry. ty’s and gajge’s runs have the same variability because they both had the same length shortest run.

The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs is the answer.

Step-by-step explanation:

given that Ty and Gajge are football players.

Carries is 15 for both and average is the same 4 for both.

But on scrutiny we find that maximum and minimum and 6 and 2 for Ty.

Hence range for Ty = 6-2 =4 (2 runs on eithre side of mean)

But for Gajge, highest is 19 and lowest is 2.

i.e. range = 19-2 =17 very much higher than that of Ty

The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs.

Option B

(B) The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs.

Step-by-step explanation:

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