Given the trigonometric equation: sin(y)=-\frac{\sqrt{3} }{2} find 3 positive solutions. explain how you found the solution : -)

Make use of your knowledge of the values of the sine function to determine angles where sin(y) = -(√3)/2. Then translate those angles to different quadrants or add different multiples of 360° (or 2π radians) as needed to find as many solutions as you want.

sin(y) = (√3)/2 for y = 60° (or π/3 radians)

The sine will be negative for angles in the 3rd and 4th quadrants whose reference angle is 60°. Those angles are 180°+60° = 240°, and 360°-60° = 300°. These are two of your solutions. You can add 360° to either of them to find another solution: 240°+360° = 600°, for example.

The solution set includes y = ...

... 240°, 300°, 600°

or

... 4π/3, 5π/3, 10π/3 radians

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.