The coordinates of a square are: (7,2), (7,7), (2,7) and

(2,2)

Step-by-step explanation:

Let's assume the four vertices of square be A(7,2), B(7,7), C(2,7) and D(x,y).

Now coordinates of vertices D needs to be found. For that use the following property of a square:

Refer to figure 1 to for understanding below calculations.

Since diagonal AC and BD bisect each other at point O(p,q). Therefore O is the mid-point of both AC and BD.

Now since O is mid-point of AC. Therefore,

Also since O is mid-point of BD. Therefore,

Similarly,

Thus coordinates of D are (2,2)

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: