Need again asap ! find the sum of the first 30 terms of the sequence below an=3n+2

= 1455

generate a few terms of the sequence using = 3n + 2

= ( 3 × 1) + 2 = 5

= (3 × 2) + 2 = 8

= (3 × 3 ) + 2 = 11

= (3 × 4 ) + 2 = 14

= ( 3 × 5 ) + 2 = 17

the terms are 5, 8, 11, 14, 17

these are the terms of an arithmetic sequence

sum to n terms is calculated using = [ 2a + (n-1)d]

where a is the first term and d the common difference

d = 8 - 5 = 11 - 8 = 14 - 11 = 3 and = 5

= [( 2 × 5) + (29 × 3) ]

= 15( 10 + 87) = 15 × 97 = 1455

45

step-by-step explanation:

a; x = 0.5

step-by-step explanation:

-10x = -5

x = 0.5