Write a slope intercept for a line passing through the point (4,-3) that is paralell to the line 4x+5y=7

First, we need to solve the equation 4x+5y=7 to make it slope intercept form and find the slope of the line, because parallel lines have the same slope.

4x+5y=7

Subtract 4x from both sides.

5y=-4x+7

Divide both sides by 5.

y=-4/5x+7/5

The slope of the line is -4/5x. Plug that in to the blank slope intercept form equation, y=mx+b, with m being the slope and b being the y-intercept.

y=-4/5x+b

Now, we need to solve for the y-intercept. We can do this by plugging in the given coordinates (4,-3) into the above equation for x and y respectively:

-3=-4/5(4)+b

-3=-16/5+b

Add -16/5 to both sides.

1/5=b

The y-intercept is 1/5, plug this into the equation:

Your equation is the above equation.

I hope this helps :)

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

exactly you go it

step-by-step explanation: