Ineed i don’t know how to graph this

Attached: The red graph is a graph of g(x) = -2x + 2

The blue grap is the graph of g'(x) = -x/2 + 1

Step-by-step explanation:

To find the inverse of g(x) = -2x + 2

First replace g(x) with y;

y = -2x + 2

Then take y to the right and x to the left;

x = -2y + 2

Solving for y gives;

2y = -x + 2

y = -x/2 + 1

Replacing y now with g'(x) gives;

g'(x) = -x/2 + 1

The graphs of g(x) = -2x + 2 and its inverse are attached.

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form