Write the equation of line in slope-intercept form. line parallel to y=0.5x+3 that passes through the point (−9,12)

The equation of line in slope-intercept form is y = 0.5x + 16.5

The standard equation of a line in slope-intercept form is expressed as:

y = mx+b where;

Given the equation;

y = 0.5x + 3

Slope m = 0.5

Express the equation of the required line in point-slope form

y - y0 = m(x-x0)

y - 12 = 0.5(x-(-9)

y - 12 = 0.5(x+9)

y - 12 = 0.5x + 4.5

y = 0.5x + 4.5 + 12

y = 0.5x + 16.5

Hence the equation of line in slope-intercept form is y = 0.5x + 16.5\

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A line parallel to the given one will have the same slope, 0.5. For the purpose here, it is convenient to start with a point-slope form of the equation, then simplify. For slope m and point (h, k), the equation of the line can be written as

... y = m(x -h) +k

We have m=0.5, (h, k) = (-9, 12), so the equation is ...

... y = 0.5(x +9) +12

... y = 0.5x +16.5

step-by-step explanation: the answer is 27. first multiply .32 by 25 which equals 8. then add 8 to 25 which gives you 33. then you subtract that from 6 since she gave 6 to her brother.

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