Will give brainliest! use the figure to complete the transformations. 1. reflect the triangle across the y-axis. 2. reflect the image across the x-axis. the final image is the same as what single transformation? a reflection across the y-axis a 180° rotation about the origin a clockwise rotation 90° about the origin

If you actually do what the problem statement tells you to do, the answer falls into your lap.

The attachment shows the triangle reflected across the y-axis (blue), then across the x-axis (red). The red triangle is clearly equivalent to the original being rotated 180° about the origin.

The appropriate choice is ...

... a 180° rotation about the origin

_____

Algebraically, reflection across the y-axis negates the x-coordinate:

... (x, y) ⇒ (-x, y)

and reflection across the x-axis negates the y-coordinate:

... (x, y) ⇒ (x, -y)

Then, reflection across first one axis then the other will result in both coordinates being negated:

... (x, y) ⇒ (-x, -y)

This is precisely what happens when a figure is rotated 180° about the origin.

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

i think the answer is fried chicken ; >

step-by-step explanation: