Jane bought a car for $30,303. the value of the car depreciated at a constant rate per year. the table below shows the value of the car after the first and second years: year 1 2 value (in dollars) 25,757.55 21,893.92 which function best represents the value of the car after t years? f(t) = 25,757.55(0.85)t f(t) = 30,303(0.85)t f(t) = 30,303 (0.15)t f(t) = 25,757.55 (0.15)t

The correct option is 2.

Step-by-step explanation:

It is given that Jane bought a car for $30,303. The value of the car depreciated at a constant rate per year.

The exponential growth and decay function is defined as

Where, P₀ is initial value and r is growth rate.

The initial value of car is $30,303. Let the rate of depreciation be x%.

It means rate of depreciation is 15%. Since the value of car decreased by 15% per year, therefore growth rate is -0.15.

Therefore option 2 is correct.

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )