Gift bags are being distributed at a birthday party. if there was a total of 140 jolly ranchers and 60 candy bars placed into gift bags, how many different combinations can be made so that there are not any pieces of candy left over? which combination has the most amount of bags? explain

Total number of jolly ranchers= 140

Total number of candy bars= 60

Now , we have to place jolly and candy into gift bags such that no pieces of candy should left.

1. Find the ratio of jolly ranchers and candy bars

 = 140/60

= 7/3

So, possible combination are (7,3),(14,6),(28,12),(35,15),(70,30).

1.So,in combination (7,3), number of bags=

                                                                  =

                                                                  =20

2. Number of Bags(14,6)=200÷20=10

3.Number of Bags(28,12)=200÷40=5

4.Number of Bags(35,15)= 200÷50=4

5.Number of Bags(70,30)=200÷100=2

Combination (1) in which there are 7 Jolly ranchers and 3 candy bars has the most amount of bags which is 20.

step-by-step explanation:

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d. 145*2 is 290 than the total angle is 360 then minus 290 then divide by two