Q25. a ladder ap of length 10m is kept against a wall ab such that it reaches a window at a, 6m high from the ground. the same ladder reaches another window at c when it is rested against the wall opposite to ab. if the walls are 14 m apart. find the height of the window at c from the ground.

Step-by-step explanation:

Given a ladder AP of length = 10m is kept against a wall AB such that it reaches a window at A, such that AB=6m .

Consider a triangle ABP

By Pythagoras theorem,

Now,The same ladder reaches another window at C when it is rested against the wall opposite to AB .

Let D be a point which represent the foot of the second building CD on the ground which is 14 m away from B.

∴ BD = BP+ PD              

⇒ 14 = 8+PD

⇒PD =14-8 = 6m

Now consider another triangle CPD

Again by Pythagoras theorem,

Therefore, the height of the window at C from the ground CD=8m

lol we need to see what the question is asking about

step-by-step explanation:

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!