To solve the equation t² - t = 12 by factoring, you would use t(t - 1) = 12 t(t - 1) - 12 = 0 (t - 4)(t + 3) = 0

t^2-t=12

t^2-t-12=0

(t-4)(t+3)=0

t=4, -t^2-t=12

t^2-t-12=0

(t-4)(t+3)=0

t=4, -t^2-t=12

t^2-t-12=0

(t-4)(t+3)=0

t=4, -t^2-t=12

t^2-t-12=0

(t-4)(t+3)=0

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb