*** will give ! *** if dg equals 88, do = 5x+12 and og =2x, find do d o g

in the number line, the end points are DG, and the point in between is O

DG = 88

DO = 5x + 12

OG = 2x

Set the equation. The two parts (DO & OG) are equal to the whole (DG)

2x + 5x + 12 = 88

Simplify. Combine like terms

(2x + 5x) + 12 = 88

7x + 12 = 88

Isolate the x. Remember to do the opposite of PEMDAS. Subtract 12 from both sides

7x + 12 (-12) = 88 (-12)

7x = 76

Isolate the x. Divide 7 from both sides:

7x/7 = 76/7

x = 76/7

Find DO. Plug in "76/7" for x:

DO = 5x + 12

DO = 5(76/7) + 12

Simplify. Remember to follow PEMDAS. Multiply 76 with 5

DO =  380/7 + 12

Next, divide 380 with 7

DO = 54.29 (rounded)

Finally, add

DO  = 54.29 + 12

DO = 66.29

66.29 is your answer

hope this helps

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

2160ft3

step-by-step explanation: