Find the linearization l(x) of the function at a. f(x) = x^4 + 2x^2, a = 1

The equation of the tangent line at x=1 can be written in point-slope form as

... L(x) = f'(1)(x -1) +f(1)

The derivative is ...

... f'(x) = 4x^3 +4x

so the slope of the tangent line is f'(1) = 4+4 = 8.

The value of the function at x=1 is

... f(1) = 1^4 +2·1^2 = 3

So, your linearization is ...

... L(x) = 8(x -1) +3

or

... L(x) = 8x -5

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step-by-step explanation:

cut 138 centimeters off

step-by-step explanation:

250-112 = 138