Joe can run the 440 yard dash in 55 seconds, and jack can run it in 88 seconds. how great a handicap must joe give jack for the boys to finish the race at the same time?

88-55=33

33 second handicap

Joe must give Jake a 33 second catch up time period

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)