25 points triangle jkl is transformed by performing a 90 degree clockwise rotation about the origin and then a reflection over the y-axis, creating triangle j’’k’’l’’. which transformation will map j’’k’’l’’ back to jkl? a reflection over the y-axis and then a 90 degree clockwise rotation about the origin a reflection over the x-axis and then a 90 degree counterclockwise rotation about the origin a reflection over the x-axis and then a 90 degree clockwise rotation about the origin a reflection over the x-axis and then a reflection over the y-axis

The correct option is: Option: C.

A reflection over the x-axis and then a 90 degree clockwise rotation about the origin

Let us suppose the vertices of the original triangle JKL as:

J(0,0), K(1,0) and L(0,1)

Hence,when the triangle is rotated 90 degree clockwise about the origin, hence the vertices of the transformation are transformed by the rule:

(x,y) → (y,-x)

J(0,0) → J'(0,0)

K(1,0) → K'(0,-1)

L(0,1) → L'(1,0)

Now when this transformed figure is reflected over the y-axis, then the rule of transformed figure are:

(x,y) → (-x,y)

Hence,

J'(0,0) → J"(0,0)

K'(0,-1) → K"(0,-1)

L'(1,0) → L"(-1,0)

Hence, the transformation is:

J(0,0) → J''(0,0)

K(1,0) → K''(0,-1)

L(0,1) → L''(-1,0)

Hence, the transformation that map J"K"L" back to JKL are:

A reflection over the x-axis and then a 90 degree clockwise rotation about the origin.

( Since, on reflecting over the x-axis, the rule of transformation is:

(x,y) → (x,-y)

J"(0,0) → J'(0,0)

K"(0,-1) → K'(0,1)

L"(-1,0) → L'(-1,0)

When the transformed image is rotated 90 degree clockwise the rule of rotation is:

(x,y) → (y,-x)

Hence,

J'(0,0) → J(0,0)

K'(0,1) → K(1,0)

L'(-1,0) → L(0,1) )

divide by 5

step-by-step explanation:

60/5 = 12

answer

explanation

the area of a circle is calculated using the formula

or

we can use any of the above formulae to calculate the required. preferably, let us use the latter since the diameter is

we substitute the diameter into the formula to get:

this is the exact value for the area of the circle.

the correct answer is a