This is a trigonometry question on right angle triangle. a bullet is found embedded in the wall of a room 2.9 m above the floor. the bullet entered the wall going upward of 38.2 degrees. how far from the wall was the bullet fired if the gun was held 1.3m above the floor?

2.857 m away from the wall. because if it is 1.3 m off the ground when fired then you just subtract that from 2.9 to get 1.6 then divide that by sin (38.2) to get 2.857 m from the wall.

the final price would be 29.6925

step-by-step explanation:

39.59 minus 25% equals 29.6925