The mean score on a driving exam for a group of driver's education students is 80 points, with a standard deviation of 3 points. apply chebychev's theorem to the data using k=2. interpret the results.

Step-by-step explanation:

Given that average or mean score on a driving exam by a group of driver's education students is 80 points, and standard deviation 3 points.

We are asked to apply Chebychev's theorem for this.

This theorem states that if x is an integrable random variable with mean = mu and std dev = sigma then

P(|X-\mu |>= k\sigma )<= {\frac {1}{k^{2}}}.

Substitute our values here.

P(|x-80|>=2(3)|<= 1/4

|x-80|>=6 mean

x is eithre less than 80-6 or greater than 80+6

i.e. probability for driving educated students getting scores not between

74 and 86 is less than 0.25

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5