Triangle abc has coordinates a(2, -5), b(1, -3), and c(6, 1). if the triangle is rotated 90° counterclockwise about the origin, what are the coordinates of b'?

Coordinate of b' would be (3,-1)

answer:

a=9

step-by-step explanation: lmk if you need a explanation

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct