You have also set up a card game in which a player picks a card from a standard deck of 52 cards. the player wins if these two events occur together: e1, in which the card drawn is a black card, and e2, in which the card drawn is a numbered card, 2 through 10.what is the probability of getting a black card and a numbered card? calculate the probabilities p(e1) and p(e2) as fractions.

First, let's count:

there are 26 possible outcomes for E1 (black card)

there are 4x9 = 36 possible outcomes for E2, to pick a numbered card (any color)

there are 2x9 =18 possible outcomes for E1 (black) AND E2 (numbered, spade + clower)

the probability of E1 AND E2 is the ratio of the count of possible outcomes for E1 + E2 and the count of all possible outcomes (52 choices to pick a card from the deck):

P(E1 and E2) = 18/52 (34.6%)

And as asked:

P(E1) = 26/52 = 1/2 (50%)

P(E2) = 36/52 = 9/13 (69.2%)

EDMENTUM / PLATO ANSWER

CAN JUST WRITE:

=  (50%)

=  (69.2%) :)))))

ipuy6tygy

step-by-step explanation:

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.