2. ⦁ justify each step in solving the equation by writing a reason for each statement. 3. ⦁ provide reasons for the proof. answer correctly, the pictures are below

1. QS bisects ∠ PQR of Δ PQR.⇒[Given]

2. ∠PQS = 90° [Given]

3.∠PQS =∠RQS ⇒[QS bisects ∠ PQR]

4. .∠PQS +∠RQS =90°  [∴∠PQS = 90°⇒given]

    2∠PQS =90°⇒  [∠PQS =∠RQS ]

   ∠PQS=45°

So,∠PQS =∠RQS =45°

2.∠ 2= ∠ 4 [Given]

⇒∠ 2≅ ∠ 4[ congruency postulate]

∠2  and ∠ 3 are supplementary.⇒°[given]

⇒∠2 + ∠ 3=180° [ By the definition of supplementary](1)

∠1 and ∠4 are supplementary.⇒[∠1 and ∠4 form linear pair.]

⇒∠1 +∠4=180°[By the definition of supplementary](2)

⇒∠2 + ∠ 3 =∠1 +∠4 [both of them are equal to 180, so they are equal to each other.⇒ Two things equal to same thing are equal to each other[Euclid postulate]]

⇒∠4 +∠3=∠1+∠4 [∠2=∠4⇒(given)]

⇒∠3=∠1   [law of cancellation]

⇒∠3≅∠1  [ Congruency property]

518,400

step-by-step explanation:

the area is multiplying all the given measurements together.

40 * 18 * 30 * 24 = 518,400

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0