Now, suppose one of the roots of the polynomial function is irrational. the roots of the function are 2, , and 5. write the equation for this polynomial function. which of the following must also be a root of the function? - the equation of the polynomial function is: f(x)=(x-2)(x-5)(x-)(x+)expand: f(x)  =  - x^{3} [/tex]+ x^{2} [/tex]+

1.  Since, the roots of the function are 2, and 5. We have to write the equation for this polynomial function.

So, the equation is .

2.  Now, the equation of the polynomial function is

We have to find its expanded form.

we will proceed from step by step to find the expanded form.

=

=

=

=

So, the expanded form of the given polynomial function is:

f(x) = = .

b. -√3

hope this helps! :o)

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )