The some of three consecutive integers is 33 more than the least of the integers. find the integers

Let the smallest number = x

The next higher number would be x +1

The 3rd number would be x +2

The sum of the 3 numbers: x + x+1 + x+2

33 more than the smallest number is written as x+33

Now you have:

x + x+1 + x+2 = x+33

Simplify the left side:

3x +3 = x +33

Subtract 3 from each side:

3x = x +30

Subtract 1x from each side:

2x = 30

Divide both sides by 2:

X = 30/2

x = 15

The three numbers are 15, 16 and 17

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00