Herky was given the following system of equations to solve. 3x-2y=17 x-3y=1 what is the solution to the system? (2,7) (20/7,67/7) (7,2) (67/7,20/7)

Option 3 (7,2) is right answer.

Step-by-step explanation:

Given two equations

3x-2y=17    ... i

x-3y=1         ... ii

We can solve this by elimination.

coefficients of x are 3 and 1 with LCD = 3

Hence multiply ii equation by 3

3x-9y = 3  ... iv

3x-2y = 17  ... i

Subtract i from iv

-7y = -14

Divide by -7

y =2

Substitute in ii

x-3(2) = 1

x=7

Hence solution is (7,2)

Verify:

We can verify our solution by substituting in i and ii.

3(7)-2(2) = 17 and 7-6 =1

Verified

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this

i dont understand the question? ?

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