40 points in a particular year, a total of 44740 students studied in two of the most popular host countries when traveling abroad. if 5672 more students studied in the most popular host country than in the second most popular host country, find how many students studied abroad in each !

I'd start with setting up the equations. Calling x the number of students in most popular country 1, and y in country 2.

x + y = 44740

x - y = 5672

now solve for x1 and x2. You can subtract second from first:

0 + 2y = 39068

y = 19534

so

x = 5672 + 19534 = 25206

Add a sentence to answer it in words.

total students= 44740 divided by 2 countries= 22370 for each country. if were trying to get a difference of 5672 students, then were gonna divide that 5672 by 2 which is gonna = 2836 students. country 1= 22370 students + 2836 of country 2's students. country 2 is 22370 students - 2836 students that we gave to country 1. so now, country 1 ends up with 25206 students, country 2 end up with 19534 students. a difference of 5672.

c: lkllmn.

hope it's you

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )