Iwill give brainl pls two planes left the same airport traveling in opposite directions. the first plane left at 9: 00 a. m. and 2.25 hours later, the two planes were 1825 miles apart. the second plane left at 10: 00 a. m. and its average rate was 108 miles per hour slower than the first plane's average rate. let x represent the first plane's average rate. what was the first plane's average rate? enter an equation that can be used to solve this problem in the first box. solve for x and enter the first plane's average rate in the second box. what is the equation and what is the

The Average rate of the first plane is 560 mph

Step-by-step explanation:

x = first plane's average rate (in mph)

x−108 = second plane's average rate (in mph)

First planes total distance = 2.25x

Second planes total distance = 1.25(x−108)

2.25x + 1.25(x−108) = 1825

x = 560

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it