Factor. 8a2−2ac+12ab−3bc a. (2a+3b)(c-4a) b. (2a+3b)(4a-c) c. (2a-3b)(4a+c) d. (2a-3b)(c-4a)

B. (2a +3b)(4a -c)

Step-by-step explanation:

Group the terms pairwise, then factor each pair.

... (8a² -2ac) +(12ab -3bc)

2a is a common factor in the first pair of terms; 3b is a common factor in the second pair of terms. We can factor those out.

... = 2a(4a -c) +3b(4a -c)

Then we see that (4a-c) is a common factor in the result. We can factor that out.

... = (2a +3b)(4a -c) . . . . matches selection B

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step-by-step explanation: