Four neighborhood children opened their own lemonade stand. the table shows the sales information for each stand, in glasses of lemonade. what was the largest fraction of sales of the stands' inventory? a. 1⁄2 b. 4⁄7 c. 3⁄4 d. 7⁄12

Option C is the answer.

Step-by-step explanation:

Given that four neighborhood children opened their own lemonade stand. The sales by the four were as follows:

A. 1⁄2

B. 4⁄7

C. 3⁄4

D. 7⁄12

We cannot compare these sales as such since they have different denominators.

To compare we find the Least common denominator for all the four first.

2,7,4,12 have lCD = 12(7) = 84

Now make equivalent fractions for all the four.

A. 1⁄2   = 42/84

B. 4⁄7    = 48/84

C. 3⁄4    = 63/84

D. 7⁄12  = 49/84

Now since denominator is the same we compare and find that

C =63/84 is the largest value.

Hence Option C is the answer.

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: