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![\dfrac{k+3}{4k-2}\cdot(12k^2+2k-4)=\dfrac{k+3}{4k-2}\cdot(12k^2-6k+8k-4}\\\\=\dfrac{k+3}{4k-2}\cdot[3k(4k-2)+2(4k-2)]=\dfrac{k+3}{4k-2}\cdot(4k-2)(3k+2)\\\\=(k+3)(3k+2)](/tpl/images/0058/1198/ef890.png)
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Multiply: k + 3/4k - 2 × ( 12k^2 + 2k - 4)...
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