Dion is at a basketball game and he wants to buy some hamburgers and drinks. his friend joe brought 2 hamburgers and 5 drinks for $8.00 and felicia brought 2 hamburgers and 3 drinks for $6.00. dion determine the cost of one hamburger and one drink

For this one, the best way to do it is write out you formulas, then solve for the first one and see if it works for the second one.

I am going to use h for hamburgers and d for drinks to make it easier.

2h+5d=8

2h+3d=6

So what I did was make the drinks 1, this way you can see if you need to raise it or if the hamburgers could come out even.  When you do that here is what it looks like:

2h+5(1)=8

2h+5=8

2h=3

h=1.50

So here is what you have as of now

h= 1.50 and d= 1

now plug that into the next problem

2h+3d=6

2(1.50)+3(1)=6

3+3=6

So that is your answer

Hamburgers are $1.50

and Drinks are $1

Hope this helps!

Hamburgers cost 1.50 each and its 1.00 for each drink

36 girls

step-by-step explanation:

the 48 boys is 4 parts of the ratio

divide 48 by 4 to obtain one part of the ratio

= 12 ← 1 part of the ratio

3 parts = 3 × 12 = 36 ← number of girls