Fred spins a spinner with five equal spaces numbered 1 thru 5 and draws a card from a standard 52-card deck. what is the probability he spins a 3 or draws a king?

Step-by-step explanation:

Given : Fred spins a spinner with five equal spaces numbered 1 thru 5 and draws a card from a standard 52-card deck.

We know that the probability of each event is given by :-

Event 1: He spins a 3.

Total outcomes for spinner with 5 equal section = 5

Then , the probability of spinning a 3 will be :-

Event 2: He draws a king.

No. of kings in a deck of cards = 4

Total number of cards in a deck of cards = 52

Then , the probability of getting a king will be :-

Since both events are independent then the probability he spins a 3 or draws a king will be the sum of probabilities each event .

Hence, the probability he spins a 3 or draws a king =

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.

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step-by-step explanation: