Which points are on the graph of the function rule ƒ(x) = 10 – 4x? ( –18, 2), ( –10, 0), ( –2, –2) (18, –2), (10, 0), (2, 2) (–2, 18), (0, 10), (2, 2) (2, –18), (0, –10), ( –2, –2)

(2, 2 ), (- 2, 18 ), (0, 10 )

substitute the x-coordinate of each point into f(x) and if the value is equal to the y-coordinate then it is on the graph of f(x)

(- 18, 2 ) ⇒ y = 10 + 72= 82 ≠ 2

(- 10, 0 ) ⇔ y = 10 + 40 = 50 ≠ 0

(- 2, - 2 )⇒ y = 10 + 8 = 18 ≠ 2

(18, - 2 ) ⇒ y = 10 - 72 = - 62 ≠ - 2

(2, 2 ) ⇒ y = 10 - 8 = 2 ⇒ (2, 2 ) is on graph

(- 2, 18 ) ⇒ y = 10 + 8 = 18 ⇒ (- 2, 18 ) is on graph

(0, 10 )⇒ y = 10 - 0 = 10 ⇒ (0, 10 ) is on graph

(2, - 18 ) ⇒ y = 10 - 8 ≠ - 18

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.