Which expression is the completely factored form of x6−64y3 ?

(x^2 - 4y)( x^4 +  4x^2y + 16y^2)

Step-by-step explanation:

x^6−64y^3

- using the identity a^3 - b^3 = (a - b)(a^2 + ab + b^2)  with a = x^2 and b = 4y we have:-

(x^2 - 4y)( x^4 +  4x^2y + 16y^2)

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2