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There is a 2/9 chance to draw two blue marbles.

Step-by-step explanation:

We have 10 marbles - 2 are yellow, 3 are pink, and 5 are blue. We want to figure out the probability of selecting two blue marbles. On the first draw, we have a half a chance (1/2) to draw a blue marble, 3/10 of a chance to draw pink, and a fifth of a chance to draw yellow (1/5). However, if we don't place the first-drawn marble back into the bag, that decrease the marble amount to 9. This means that drawing blue has a 4/9 chance now, pink has a 2/9 chance now, OR yellow has a 1/9 chance now. However, blue is still the highest probability. The hint states how we multiply the probabilities of both the first and second events together. 1/2 x 4/9 = 4/18 which is simplified to 2/9. There is a 2/9 chance to draw two blue marbles.

i need a picure

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)