Find the solution set to each equation. show all work! a) 3x^2 +27x=0 b) (x-3)(x+2)(3x-6)=0 c) x(x-5)+8(x-5)=0

a) is  x=0,-9

b) is x=3,±2

c) is x=5,−8

Step-by-step explanation:

a) 3x^2 +27x=0

1. Factor out the common term 3x

3x(x+9)=0

2. Solve for x

x=0,−9

Answer is x=0,-9

b)  (x-3)(x+2)(3x-6)=0

1. Ask: When will (x-3)(x+2)(3x-6) equal zero?

When x-3=0, x+2=0 or 3x-6=0

Solve each of the 3 equations above

x=3,±2

x=3,±2

c) x(x-5)+8(x-5)=0

1. Factor out the common term x-5

(x−5)(x+8)=0

2.Solve for x

x=5,−8

Answer is x=5,−8

the square root of what number? if you add that, then someone will probably answer the question.