Which coordinate (g, z) lies in the solution set for the following system of inequalities? 3g + 4z < 24 3g - 4z > 12 select one or more: a. (4, 2) b. (6, 1) c. (-2, 8) d. (3, 9)

B. (6, 1)

Step-by-step explanation:

A graph of the solution space shows that the point (6, 1) is the only one that satisfies both inequalities.

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Verification

3(6) +4(1) = 18 +4 = 22 < 24

3(6) -4(1) = 18 -4 = 14 > 12

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Notes on the Solution

The graphing calculator used here only recognizes variables x and y. Since g is the first variable in the ordered pair (g, z) we use x to represent g in the equations that are graphed. Similarly, y is used to represent z in the graphed equations.

You graph an inequality by graphing it as though it were an equation, then choosing the appropriate half-plane (one side of the line or the other) to shade as the solution space. Where the shadings from the two inequalities overlap, both are satisfied by points in that area.

In the first inequality, x and y values that are less than those on the line will satisfy the inequality, so the shading is below the line.

In the second inequality, x values greater than those on the line will satisfy the inequality, so the shading is to the right of the line.

In both cases, the line is graphed as a dashed line. This is because the points on the line do not satisfy the < or > conditions, so are not part of the solution set. (If one or both conditions were ≤ or ≥, then the corresponding line would be solid, and the points on the line would be part of the solution.)

you should pay $0.88

what is the image?

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.