Arocket is divided into 3 sections. the top section is one -sixth the length of the bottom section. the middle section is one -half the length bottom section. the total length of the rocket is 240 ft. find the length of the top section

Let the bottom section has length x feet.

1. The top section is the length of the bottom section, then the length of the top section is

2. The middle section is the length bottom section, then the middle section has length

3. The total length of the rocket is

that is 240 feet.

Thus, you have the equation

4. Solve it. Multiply this equation by 6:

Divide it by 10:

The length of the bottom section is 144 feet, then the length of the top section is

The top section has length 24 feet

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺