What is the zeros and graph of f(x)=1/2(x+5)(x+1)(x-2)

When you write a polynomial in the form

You know that you have a polynomial of degree , which crosses the x axis at

So, in your case, you have a cubic which crosses the x axis at x=-5, x=-1 and x=2.

Moreover, since A=1/2 is positive, the end behaviour of the cubic is preserved, i.e.

This is all the information you need to sketch a first draft of the graph.

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680