Mr. piper is driving roddy and scott home from school. they both want to ride in the front seat. how can he make a fair decision about who rides in the front seat? select all of the correct answers. a. put each person's name on a separate piece of paper in a bag. randomly draw the winning name. b. flip a coin twice. if both tosses are heads, roddy wins. if one is heads and one is tails, scott wins. c. roll a number cube. if it lands on 1 or 2, roddy wins. if it lands on any other number, scott wins. d. roll a number cube. if it lands on an even number, roddy wins. if it lands on an odd number, scott wins.

A.Put each person's name on a separate piece of paper in a bag. Randomly draw the winning name; and D.Roll a number cube. If it lands on an even number, Roddy wins. If it lands on an odd number, Scott wins.

Step-by-step explanation:

In order for it to be a fair decision, both boys have to have an equal chance of being selected.

For choice A, drawing their names from a bag, both names are equally likely to be chosen; that makes this fair.

For choice B, there is 1 way to get both heads when flipping a coin.  There are 2 ways to get heads and tails when flipping a coin.  This gives Scott a greater chance, so this is not fair.

For choice C, there are 2 ways to get a 1 or a 2.  There are 4 ways to get anything else.  This gives Scott a greater chance, so this is not fair.

For choice D, there are 3 even numbers and 3 odd numbers.  Both boys have an equal chance, so this is fair.

the answer is 489

step-by-step explanation:

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x