The value of " x " 2x + y − z = 3 −x + y + 2z = 0 3x + 2y + z = 9 12 2 3 -4

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Step-by-step explanation:

If you multiply the first equation by 2 and add the second, you eliminate z from the resulting equation.

If you add the first and third equations, you also eliminate z from the result.

Both of these resulting equations will have 3y as their second term, so you can subtract the first result from the second to eliminate the y variable and find the value of x.

This process has a shortcut. If we call the equations A, B, and C, the first elimination is done by calculating 2A+B. The second elimination calculates A+C. To find x, we compute ...

... (A+C) -(2A+B) = -A -B +C

... -(2x +y -z) -(-x +y +2z) +(3x +2y +z) = -3 -0 +9

... x(-2+1+3) +y(-1-1+2) +z(1-2+1) = 6

... 2x = 6

... x = 3

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Since this is a college math question, we presume you have a graphing calculator and are expected to know how to use it. The solution to systems of linear equations on such a calculator is usually pretty simple. A TI-84 can tell you the values of x, y, and z pretty easily: (x, y, z) = (3, -1, 2).

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3.how is solving radical equations different than solving linear equations?

step-by-step explanation: