11.) -4 = 2/5 x a. x = 10 b. x = -10 c. x = -1 d. x = 1 12.) which equation is an identity? a. 11 - (2v + 3) = -2v - 8 b. 5w + 8 - w = 6w - 2(w - 4) c. 7m - 2 = 8m + 4 - m d. 8y + 9 = 8y - 3 13.) which equation has no solution? a. 8 - (5v + 3) = 5v - 5 b. 3m - 6 = 5m + 7 - m c. 3w + 4 - w = 5w - 2(w- 2) d. 7y + 9 = 7y - 6 14.) solve the equation 5(z-4) - z = 4z - 20 a. 4 b. -4 c. infinity many solutions d. no solution 15.) 3 + 6z = 13 + 6z a. z = -5/6 b. z = 2 2/3 c. z = infinity many solutions d. z = no solutions 17 . solve the equation . 6(z - 2) +4 = 10 a. z = 2 b. z = 3 c. z = -3 d. z = -4 18.) solve the equation . 96 = -6(-4 - 3y) a. y = 2 b. y = 4 c. y = -2 d. y = -4 19.) solve the equation . -4y + 8 = 4(2y - 2) -2(-16 + 8y) a. y = -4 b. y = 4 c. y = -2 d. y = -6

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

figure c

step-by-step explanation:

hope this .

y=sec x is the correct answer

~batmans wife dun dun